Q. The solution of the equation $\sin^{10}{2x = 1 + \cos^{10}x}$ is
A) $x = (2n + 1)\frac{\pi}{2}$
B) $x = n\pi$
C) $x = (2n + 1)\frac{\pi}{4}$
D) None of these
Explanation
(d)
We have, $\sin^{10}{2x = 1 + \cos^{10}x}$
Minimum value of RHS = 1 and maximum values of LHS = 1. Therefore, solution is possible only when $\sin^{10}{2x = 1}$ and $\cos^{10}x = 0$. But this is not possible. Therefore, it has no solution.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.