Q. For all $n \in N$ , $2 \bullet 4^{2n + 1} + 3^{3n + 1}$ is divisible by
A) 2
B) 9
C) 3
D) 11
Explanation
(d)
Let $P(n) = 2 \bullet 4^{2n + 1} + 3^{3n + 1}$
$P(1) \equiv 128 + 81 = 209$(divisible by 11 only)
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.