Q. If $y = 2^{1/\log_{x}{(8)}}$, then $x$ is equal to
A) $y$
B) $y^{2}$
C) $y^{3}$
D) None of these
Explanation
(c)
Given, $y = 2^{1/\log_{x}{(8)}} = 2^{\log_{8}{(x)}}$
$\Rightarrow y = 2^{\log_{2}\sqrt[3]{x}} = \sqrt[3]{x}$
$\Rightarrow x = y^{3}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.