(d) Since, $x^{2} - 3|x| + 2 = 0$ $\Rightarrow \ \ \left( |x| - 2 \right)\left( |x| - 1 \right) = 0$ $\Rightarrow |x| = 2$ or $|x| = 1$ $\Rightarrow x = \pm 2$ or $x = \pm 1$ $\therefore$ The given equation has four real roots
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Ph.D. in Physics with 19+ years of teaching experience.