Q. The equation $x^{2} - 3|x| + 2 = 0$ has

A) No real root
B) One real root
C) Two real roots
D) Four real roots
Explanation

(d)
Since, $x^{2} - 3|x| + 2 = 0$
$\Rightarrow \ \ \left( |x| - 2 \right)\left( |x| - 1 \right) = 0$
$\Rightarrow |x| = 2$ or $|x| = 1$
$\Rightarrow x = \pm 2$ or $x = \pm 1$
$\therefore$ The given equation has four real roots

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.