Q. If $n$ is a positive integer, then $\left( 1 + i\sqrt{3} \right)^{n} + \left( 1 - i\sqrt{3} \right)^{n}$ is equal to

A) $2^{n - 1}\cos\frac{n\pi}{3}$
B) $2^{n}\cos\frac{n\pi}{3}$
C) $2^{n + 1}\cos\frac{n\pi}{3}$
D) None of these
Explanation

(c)
$\left( 1 + i\sqrt{3} \right)^{n} + \left( 1 - i\sqrt{3} \right)^{n}$
$= 2^{n}\left\lbrack \left( \frac{1}{2} + \frac{i\sqrt{3}}{2} \right)^{n} + \left( \frac{1}{2} - \frac{i\sqrt{3}}{2} \right)^{n} \right\rbrack$
$= 2^{n}\left\lbrack \left( \cos{\frac{\pi}{3} + i\sin\frac{\pi}{3}} \right)^{n} + \left( \cos{\frac{\pi}{3} - i\sin\frac{\pi}{3}} \right)^{n} \right\rbrack$
$= 2^{n}\left\lbrack 2\cos\frac{n\pi}{3} \right\rbrack = 2^{n + 1}\cos\frac{n\pi}{3}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.