Q. If the roots of the equation $x^{2} - bx + c = 0$ are two consecutive integers, then $b^{2} - 4c$ is

A) $- 1$
B) 0
C) 1
D) 2
Explanation

(c)
Let $\alpha$ and $\beta$ are the roots then
$\alpha + \beta = b,\ \alpha\beta = c$
Given, $|\alpha - \beta| = 1$
$\Rightarrow (\alpha + \beta)^{2} - 4\alpha\beta = 1$
$\Rightarrow b^{2} - 4c = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.