If $a + b + c = 0$, then the roots of the equation $4ax^{2} + 3bx + 2c = 0$ are

Question

Dr. Abubacker · Accepted Answer

(c)
We have, $a + b + c = 0$ …(i)
Let $D = B^{2} + 4AC$
$= 9b^{2} - 4(4a)(2c) = 9b^{2} - 32ac$
$= 9(a + c)^{2} - 32ac$ [from Eq. (i)]
$= 9(a - c)^{2} + 4ac$
Hence, roots are real.

Q. If $a + b + c = 0$, then the roots of the equation $4ax^{2} + 3bx + 2c = 0$ are

Explanation

Reviewed by Dr. Abubacker

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