Q. $A$ And $B$ are two points on the Argand plane such that the segment $AB$ is bisected at the point$(0,\ 0)$. If the point $A$, which is in the third quadrant has principle amplitude $\theta$, then the principle amplitude of the point $B$ is

A) $- \theta$
B) $\pi - \theta$
C) $\theta - \pi$
D) $\pi + \theta$
Explanation

(c)
From the figure it is clear that amplitude of point
$B = \theta - \pi$
[image:5_image10.emf]

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.