Q. If $a,\ b,\ c \neq 0$ and belongs to the set $\{ 0,\ 1,2,\ 3,\ \ldots\ldots..,\ 9\}$, Then $\log_{10}\left( \frac{a + 10b + 10^{2}c}{10^{- 4}a + 10^{- 3}b + 10^{- 2}c} \right)$ is equal to

A) 1
B) 2
C) 3
D) 4
Explanation

(d)
$\log_{10}\left( \frac{a + 10b + 10^{2}c}{10^{- 4}a + 10^{- 3}b + 10^{- 2}c} \right)$
$= \log_{10}\left( \frac{a + 10b + 10^{2}c}{\frac{1}{10^{4}}(a + 10b + 10^{2}c)} \right)$
$= \log_{10}{10^{4} = 4}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.