(b)
Given, $x = \log_{b}{a = \frac{\log_{e}a}{\log_{e}b}}$
$y = \log_{c}{b = \frac{\log_{e}b}{\log_{e}c}}$
And $z = \log_{a}{c = \frac{\log_{e}c}{\log_{e}a}}$
$\therefore\ \ \ \ \ \ \ xyz = \frac{\log_{e}a}{\log_{e}b}.\frac{\log_{e}b}{\log_{e}c}.\frac{\log_{e}c}{\log_{e}a} = 1$