Q. If $1,\ \omega,\ \omega^{2}$ are the cube roots of unity, then $\left( 3 + \omega^{2} + \omega^{4} \right)^{6}$ is equal to
A) 64
B) 729
C) 2
D) 0
Explanation
(a)
$\left( 3 + \omega^{2} + \omega^{4} \right)^{6} = \left( 3 + \omega^{2} + \omega \right)^{6} = (3 - 1)^{6} = 64$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.