Q. The value of $a$ for which the equation $2x^{2} + 2\sqrt{6}x + a = 0$ has equal root, is
A) 3
B) 4
C) 2
D) $\sqrt{3}$
Explanation
(a)
Since, roots are equal
$\therefore\left( 2\sqrt{6} \right)^{2} = 4.2.a$
$\Rightarrow \ \ 24 = 8a$
$\Rightarrow a = 3$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.