Q. If $w = \alpha + i\beta$, where $\beta \neq 0$ and $z \neq 1$, satisfies the condition that $\left( \frac{w - \overline{w}z}{1 - z} \right)$ is purely real, then the set of values of $z$ is

A) $|z| = 1,\ z \neq 2$
B) $|z| = 1$ and $z \neq 1$
C) $z = \overline{z}$
D) None of these
Explanation

(b)
Let $z_{1} = \frac{w - \overline{w_{z}}}{1 - z}$ be purely real
$\Rightarrow \ \ \ \ z_{1} = \overline{z_{1}}$
$\therefore\ \ \ \ \ \ \frac{w - \overline{w}z}{1 - z} = \frac{\overline{w} - w\overline{z}}{1 - \overline{z}}$
$\Rightarrow \ \ \ \ \ \ \ w - w\overline{z} - \overline{w}z + \overline{w}z\ \overline{z}$
$= \ \ \ \ \overline{w} - z\overline{w} - w\overline{z} + wz\ \overline{z}$
$\Rightarrow \ \ \ \ \left( w - \overline{w} \right) + \left( \overline{w} - w \right)|z|^{2} = 0$
$\Rightarrow \ \ \ \ \ \ \left( w - \overline{w} \right) + \left( 1 - |z|^{2} \right) = 0$
$\Rightarrow \ \ \ \ |z|^{2} = 1$
[as, $w - \overline{w} \neq 0,$ since $\beta \neq 0$]
$\Rightarrow \ \ \ \ \ |z| = 1$ and $z \neq 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.