Q. The value of $\log_{2}{20\log_{2}{80 - \log_{2}{5\log_{2}320}}}$ is equal to

A) 5
B) 6
C) 7
D) 8
Explanation

(d)
$\log_{2}{20\log_{2}{80 - \log_{2}{5\log_{2}320}}}$
$= \log_{2}{\left( 2^{2} \times 5 \right)\log_{2}{\left( 2^{4} \times 5 \right) - \log_{2}{5\log_{2}{(2^{6} \times 5)}}}}$
$= \left( 2 + \log_{2}5 \right)\left( 4 + \log_{2}5 \right) - \log_{2}{5(6 + \log_{2}5)}$
$= 8 + 6\log_{2}{5 + \left( \log_{2}5 \right)^{2} - 6\log_{2}{5 - \left( \log_{2}5 \right)^{2} = 8}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.