If $\arg{(z) = heta}$ then $\arg\left( \overline{z} ight)$ is equal to

Question

If $\arg{(z) = 	heta}$ then $\arg\left( \overline{z} ight)$ is equal to

Dr. Abubacker · Accepted Answer

(d)
Let $z = a + ib$
$	herefore\ \ \arg{(z) = 	heta = 	an^{- 1}\frac{b}{a}}$
$\because\ \ \ \overline{z} = a - ib$
$	herefore\ \arg{\left( \overline{z} ight) = 	an^{- 1}{\left( - \frac{b}{a} ight) = - 	an^{- 1}{\left( \frac{b}{a} ight) = - 	heta}}}$

Q. If $\arg{(z) = \theta}$ then $\arg\left( \overline{z} \right)$ is equal to

Explanation

Reviewed by Dr. Abubacker

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