If $z_{1} = \sqrt{2}\left( \cos{\frac{\pi}{4} + i\sin\frac{\pi}{4}} \right)$ And $z_{2} = \sqrt{3}\left( \cos{\frac{\pi}{3} + i\sin\frac{\pi}{3}} \right)$, then $\left| z_{1}z_{2} \right|$ is

Question

Dr. Abubacker · Accepted Answer

(c)
$\left| z_{1} ight| = \sqrt{2},\ \ \left| z_{2} ight| = \sqrt{3}$
$	herefore\ \ \ \ \ \ \left| z_{1}z_{2} ight| = \left| z_{1} ight||z_{2} = \sqrt{6}$

Q. If $z_{1} = \sqrt{2}\left( \cos{\frac{\pi}{4} + i\sin\frac{\pi}{4}} \right)$ And $z_{2} = \sqrt{3}\left( \cos{\frac{\pi}{3} + i\sin\frac{\pi}{3}} \right)$, then $\left| z_{1}z_{2} \right|$ is

Explanation

Reviewed by Dr. Abubacker

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