The value of $\log_{2}{\log_{2}{\log_{4}{256 + 2\log_{\sqrt{2}}2}}}$ is

Question

Dr. Abubacker · Accepted Answer

(d)
$\log_{2}{\log_{2}{\log_{4}{256 + 2\log_{\sqrt{2}}2}}}$
$= {\log_{2}{\log_{2}{\log_{4}(4)}}}^{4} + 2\frac{1}{\log_{2}\sqrt{2}}$
$= \log_{2}{\log_{2}{4 + \frac{4}{\log_{2}2}}}$
$= \log_{2}{2 + 4 = 1 + 4 = 5}$

Q. The value of $\log_{2}{\log_{2}{\log_{4}{256 + 2\log_{\sqrt{2}}2}}}$ is

Explanation

Reviewed by Dr. Abubacker

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