(b) Given, $z = - \overline{z}$ $\Rightarrow \ \ \ \ \ x + iy = - \overline{(x + iy)}$ [Put $z = x + iy$] $\Rightarrow \ \ \ \ x + iy = - (x - iy)$ $\Rightarrow \ \ \ \ x = 0$ Hence, $z$ is a purely imaginary.
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.