Q. The maximum number of real roots of the equation $x^{2n} - 1 = 0$ is
A) 2
B) 3
C) $n$
D) $2n$
Explanation
(a)
Let, $f(x) = x^{2n} - 1$
At $x = \pm 1,\ f(x) = 0$
Hence, for no other real value of $x,\ f(x)$ is zero
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.