Q. $7^{2\log_{7}5}$ is equal to
A) $\log_{7}35$
B) 5
C) 25
D) $\log_{7}25$
Explanation
(c)
$7^{2\log_{7}5} = 7^{\log_{7}(5)^{2}}$
$= (5)^{2} = 25\ \ \ \ \ \lbrack\because a^{\log_{a}x} = x;x > 0,\ x \neq 0,\ 1\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.