Q. The value of $\sqrt{i}$ is
A) $1 - i$
B) $1 + i$
C) $i - 1$
D) $\pm \frac{1}{\sqrt{2}}(1 + i)$
Explanation
(d)
$\sqrt{i} = \sqrt{\frac{2i}{2}} = \frac{1}{\sqrt{2}}\sqrt{2i + 1 + i^{2}}$
$= \frac{1}{\sqrt{2}}\sqrt{(1 + i)^{2}} = \pm \frac{1}{\sqrt{2}}(1 + i)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.