Q. The conjugate of the complex number $\frac{(1 + i)^{2}}{1 - i}$ is

A) $1 - i$
B) $1 + i$
C) $- 1 + i$
D) $- 1 - i$
Explanation

(d)
Given complex number is
$\frac{(1 + i)^{2}}{1 - i} = \frac{(1 + i^{2} + 2i)}{1 - i} \times \frac{1 + i}{1 + i} = \frac{2i + 2i^{2}}{1 + 1} = i - 1$
$\therefore$ Required conjugate is $- i - 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.