Q. The equation $\mathcal{z}^{2} = \overline{\mathcal{z}}$ has
A) No solution
B) Two solutions
C) Four solutions
D) An infinite number of solutions
Explanation
(c)
We have, $\mathcal{z}^{2} = \overline{\mathcal{z}}$
On multiplying by $\mathcal{z}$ both sides (if $\mathcal{z} \neq 0)$,
$\mathcal{z}^{3} = 1$ has three solutions and $\mathcal{z} = 0$ is also a solution
So, total number of solution is 4
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.