Q. If $\log_{4}{2 + \log_{4}4 + \log_{4}{x + \log_{4}{16 = 6}}}$, then the value of $x$ is
A) 64
B) 4
C) 8
D) 32
Explanation
(d)
We have,
$\log_{4}{2 + \log_{4}{4 + \log_{4}{x + \log_{4}{16 = 6}}}}$
$\Rightarrow \log_{4}{(2 \times 4 \times x \times 16)} = 6$
$\Rightarrow 128x = 4^{6}$
$\Rightarrow x = \frac{4^{3}}{2} = 32$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.