Q. The argument of the complex number $\frac{13 - 5i}{4 - 9i}$ is
A) $\pi/3\$
B) $\pi/4$
C) $\pi/5$
D) $\pi/6$
Explanation
(b)
Let $z = \frac{13 - 5i}{4 - 9i} \times \frac{4 + 9i}{4 + 9i} = \frac{97 + 97i}{97} = 1 + i$
$\therefore\ \ \ \arg{(z) = \tan^{- 1}{\left( \frac{1}{1} \right) = \frac{\pi}{4}}}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.