Q. If $\alpha\$and$\ \beta$ are the roots of the equation $x^{2} - x + 1 = 0$ then $\alpha^{2009} + \beta^{2009}$ is equal to

A) $- 2$
B) $- 1$
C) 1
D) 2
Explanation

(c)
$\alpha$ and $\beta$ are roots of the equation
$x^{2} - x + 1 = 0$
$\Rightarrow \ \alpha + \beta = 1,\ \alpha\beta = 1$
$\Rightarrow \ \alpha = - \omega,\ \beta = - \omega^{2}$
or $\alpha = - \omega^{2},\ \beta = - \omega$
Taking $\alpha = - \omega,\ \beta = - \omega^{2}$
$\alpha^{2009} + \beta^{2009} = ( - \omega)^{2009} - \left( - \omega^{2} \right)^{2009}$
$= - (\omega^{2} + \omega)$
$= 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.