Q. Let $2\sin^{2}{x + 3\sin{x - 2 > 0\ and\ x^{2} - x - 2 < 0},}$ ($x$ is measured in radians). Then $x$ lies in the interval
A) $\left( \frac{\pi}{6},\frac{5\pi}{6} \right)$
B) $\left( \ - 1,\frac{5\pi}{6} \right)$
C) $( - 1,\ 2)$
D) $\left( \ \frac{\pi}{6},2 \right)$
Explanation
The correct answer is Option D: $\left( \ \frac{\pi}{6},2 \right)$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.