Q. If one root of the equation $x^{2} + (l - 3i)x - 2(l + i) = 0$ is $- l + i$, then the other root is
A) $- l - i$
B) $\frac{- l - i}{2}$
C) $i$
D) $2i$
Explanation
(d)
Let another root of equation
$x^{2} + (1 - 3i)x - 2(1 + i) = 0$ is $\alpha$
$\therefore\ \ \ \alpha + ( - 1 + i) = - (1 - 3i)$
$\Rightarrow \ \ \alpha = 2i$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.