Q. If the roots of the equation $x^{2} - bx + c = 0$ be two consecutive integers, then $b^{2} - 4c$ equals

A) 1
B) 2
C) 3
D) -2
Explanation

(a)
Let two consecutive integers $n$ and $(n + 1)$ be the roots of $x^{2} - bx + c = 0$. Then, $n + (n + 1) = b$ and $n(n + 1) = c$
$\therefore\ \ b^{2} - 4c = (2n + 1)^{2} - 4n(n + 1) = 1$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.