Q. If $a,c \neq 0$ and $\alpha,\beta$ are the roots of the equation $ax^{2} + bx + c = 0$, then the quadratic equation with $1/\alpha$ and $1/\beta$ as its root is

A) $x^{2}/a + x/b + 1/c = 0$
B) $cx^{2} + bx + a = 0$
C) $bx^{2} + cx + a = 0$
D) $ax^{2} + cx + b = 0$
Explanation

(b)
Here, $\alpha + \beta = - \frac{b}{a}$ and $\alpha\beta = \frac{c}{a}$
Sum of the given roots$= \frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha\beta} = - \frac{b}{c}$
And product of the given roots$= \frac{1}{\alpha}.\frac{1}{\beta} = \frac{a}{c}$
$\therefore$Required equation is
$x^{2} -$(sum of roots)$x +$product of roots=0
$\Rightarrow x^{2} + \frac{b}{c}x + \frac{a}{c} = 0$
$\Rightarrow \ \ cx^{2} + bx + a = 0$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.