(b) Conjugate of $\frac{2 - 3i}{4 - i}$ is $\frac{2 + 3i}{4 + i}$ $\therefore\ \ \ \ \ \frac{2 + 3i}{4 + i} = \frac{2 + 3i}{4 + i} \times \frac{4 - i}{4 - i}$ $= \frac{8 + 3 - 2i + 12i}{16 + 1}$ $= \frac{11 + 10i}{17}$
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Ph.D. in Physics with 19+ years of teaching experience.