Q. The number which exceeds its positive square roots by 12, is

A) 9
B) 16
C) 25
D) None of these
Explanation

(b)
Let the required number is $x$.
According to given condition
$x = \sqrt{x} + 12$
$\Rightarrow x - 12 = \sqrt{x}$
$\Rightarrow x^{2} - 25x + 144 = 0$
$\Rightarrow x^{2} - 16x - 9x + 144 = 0$
$\Rightarrow x = 16,\ 9$
Since $x = 9$ does not hold the condition.
$\therefore x = 16$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.