If $a + b + c = 0$, then the roots of the equation $4ax^{2} + 3bx + 2c = 0$ are

Question

Dr. Abubacker · Accepted Answer

(c)
Given, $a + b + c = 0,\ \ 4ax^{2} + 3bx + 2c = 0$
Now, $D = 9b^{2} - 4(4a)(2c)$
$= 9(a + c)^{2} - 32ac = 9(a - c)^{2} + 4ac > 0$
Hence, roots are real

Q. If $a + b + c = 0$, then the roots of the equation $4ax^{2} + 3bx + 2c = 0$ are

Explanation

Reviewed by Dr. Abubacker

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