Q. The square roots of $- 7,\ - 24\sqrt{- 1}$ are

A) $\pm (4 + 3\sqrt{- 1})$
B) $\pm (3 + 4\sqrt{- 1})$
C) $\pm (3 - 4\sqrt{- 1})$
D) $\pm (4 - 3\sqrt{- 1})$
Explanation

(c)
$\sqrt{- 7 - 24\sqrt{- 1}} = \sqrt{- 1}\sqrt{7 + 24i}$
We know
$\sqrt{a + ib} = \pm \left\lbrack \sqrt{\frac{1}{2}(\sqrt{a^{2} + b^{2}} + a)} + i\sqrt{\frac{1}{2}(\sqrt{a^{2} + b^{2}} - a)} \right\rbrack$
$\therefore i\sqrt{7 + 24i}$
$= i\left\lbrack \pm \left\{ \sqrt{\frac{1}{2}(\sqrt{49 + 576} + 7)} + i\sqrt{\frac{1}{2}(\sqrt{49 + 576} - 7)} \right\} \right\rbrack$
$= i\left\lbrack \pm \left\{ \sqrt{\frac{1}{2}(32)} + i\sqrt{\frac{1}{2}(18)} \right\} \right\rbrack$
$= \pm (3 - 4\sqrt{- 1}$)

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.