(a)
If $\arg{(z) = - \pi + \theta}$
$\Rightarrow \ \ \ \ \ \ \arg{\left( \overline{z} \right) = \pi - \theta}$
$\arg{\left( - \overline{z} \right) = - \theta}$
$\arg{\left( \overline{z} \right) - \arg{\left( - \overline{z} \right) = \pi - \theta - ( - \theta) = \pi - \theta + \theta = \pi}}$