Q. If $- \pi < \arg{(z) < - \frac{\pi}{2}}$ then $\arg{\left( \overline{z} \right) - \arg{( - \overline{z})}}$ is

A) $\pi$
B) $- \pi$
C) $\pi/2$
D) $- \pi/2$
Explanation

(a)
If $\arg{(z) = - \pi + \theta}$
$\Rightarrow \ \ \ \ \ \ \arg{\left( \overline{z} \right) = \pi - \theta}$
$\arg{\left( - \overline{z} \right) = - \theta}$
$\arg{\left( \overline{z} \right) - \arg{\left( - \overline{z} \right) = \pi - \theta - ( - \theta) = \pi - \theta + \theta = \pi}}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.