If $(1 - p)$ is a root of quadratic equation $x^{2} + px + (1 - p) = 0$, then its roots are

Question

Dr. Abubacker · Accepted Answer

(c)
Since, $(1,\  - p)$ is the root of given equation so it will satisfy the given equation
$	herefore\ \ \ (1 - p)^{2} + p(1 - p) + (1 - p) = 0$
$\Rightarrow \ \ (1 - p)\lbrack 1 - p + p + 1brack = 0$
$\Rightarrow p = 1$
On putting the value of $p$ in given equation, we get
$x^{2} + x = 0\ \ \  \Rightarrow \ \ \ \ x = 0,\  - 1$

Q. If $(1 - p)$ is a root of quadratic equation $x^{2} + px + (1 - p) = 0$, then its roots are

Explanation

Reviewed by Dr. Abubacker

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