Q. The value of $x$ which satisfy the equation $\sqrt{5x^{2} - 8x + 3} - \sqrt{5x^{2} - 9x + 4}\ = \sqrt{2x^{2} - 2x} - \sqrt{2x^{2} - 3x + 1}$ is

A) 3
B) 2
C) 1
D) 0
Explanation

(c)
$\because\ \sqrt{5x^{2} - 8x + 3} - \sqrt{5x^{2} - 9x + 4} = \sqrt{2x^{2} - 2x} - \sqrt{2x^{2} - 3x + 1}$
Also, $\left( 5x^{2} - 8x + 3 \right) - \left( 5x^{2} - 9x + 4 \right) = \left( 2x^{2} - 2x \right) - (2x^{2} - 3x + 1)$
$\Rightarrow \ x - 1 = x - 1$
$\Rightarrow \ x = 1$ is the required value.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.