If $(x^{2} - 3x + 2)$ is a factor of $x^{4} - px^{2} + q = 0$, then the values of $p$ and $q$ are

Question

Dr. Abubacker · Accepted Answer

(b)
We have, $x^{2} - 3x + 2 = 0\ \ \  \Rightarrow \ \ \ \ (x - 1)(x - 2) = 0$
$\Rightarrow \ \ \ \ x = 1.2$
For $x = 1,\ x^{4} - px^{2} + q = 0\  \Rightarrow \ 1 - p + q = 0$ ...(i)
For $x = 2,\ \ \ \ \ \ \ 16 - 4p + q = 0$ ...(ii)
On solving Eqs. (i) and (ii), we get
$p = 5,\ \ \ \ q = 4$

Q. If $(x^{2} - 3x + 2)$ is a factor of $x^{4} - px^{2} + q = 0$, then the values of $p$ and $q$ are

Explanation

Reviewed by Dr. Abubacker

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