Q. The coefficient of $x$ in the equation $x^{2} + px + q = 0$ was taken as 17 in place of 13 its roots were found to be $- 2\ and - 15$. The roots of the original equation are

A) 3 ,10
B) $- 3,\ - 10$
C) $- 5,\ - 8$
D) None of these
Explanation

(b)
Let the equation (incorrectly written form) be
$x^{2} + 17x + q = 0$
Since, roots are $- 2,\ - 15.$
$\therefore q = 30$
So, correct equation is $x^{2} + 13x + 30 = 0$
$\Rightarrow x^{2} + 10x + 3x + 30 = 0$
$\Rightarrow (x + 3)(x + 10) = 0$
$\Rightarrow x = - 3,\ - 10$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.