(d) $y^{x^{2} + 7x + 12} = 1$ $\Rightarrow x^{2} + 7x + 12 = 0$ $\Rightarrow x = - 3,\ - 4$ $\Rightarrow y = 9,\ 10$ (when $y \neq 1)$ Again when $y = 1,\ x = 5.$ $\therefore Solutions\ are\ ( - 3\ ,9),( - 4,\ 10),\ (5,\ 1)$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.