Q. Cell-A has osmotic potential of -18 bars and pressure potential of 8 bars, whereas, cell-B has osmotic potential of -14 bars and pressure potential 2 bars. The direction of flow of water will be

A) From cell-B to cell-A
B) From cell-A to cell-B
C) No flow of water
D) In both the directions
Explanation

The water potential ($\Psi$) is equal to osmotic potential ($\Psi_{s}$) + pressure potential ($\Psi_{p}$). Osmotic potential is always in negative value. The water potential is the chemical potential of water, which is equivalent to DPD with negative sign. Therefore, water potential ($\Psi_{A}$) of cell-A is $\Psi_{A} = \Psi_{s} + \Psi_{p}$=-18+8=-10 Water potential of cell-B($\psi_{B}$) is $\Psi_{B} = \Psi_{s} + \Psi_{p}$=-14+2=-12 Since, water moves from higher water potential, the flow of water will be from cell-A (-10 bars) to cell-B (-12 bars).

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.