Q. The value of $\frac{\log_{3}{5 \times \log_{25}{27 \times \log_{49}7}}}{\log_{81}3}$ is

A) 1
B) 6
C) $\frac{2}{3}$
D) 3
Explanation

(d)
$\frac{\log_{3}{5.\log_{25}{27.\log_{49}7}}}{\log_{81}3}$
$= \frac{\frac{\log 5}{\log 3}.\frac{3}{2}.\frac{\log 3}{\log 5}.\frac{1}{2}}{\frac{1}{4}}$
$= 3$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.