The coefficients of $x$ in the quadratic equation $x^{2} + bx + c = 0$ was taken as 17 in place of 13, its roots were found to be -2 and -15. The correct root of the original equation are

Question

Dr. Abubacker · Accepted Answer

(a)
Given that, $x^{2} + bx + c = 0$ and $b = 17$ ...(i)
Since, roots of this equation are $- 2$ and $- 15$
$	herefore\ \ (x + 2)(x + 15) = x^{2} + 17x + 30$ ...(ii)
From Eqs. (i) and (ii), $c = 30$
If $b = 13$, then
$x^{2} + 13x + c = 0\ \ \  \Rightarrow \ \ \ x^{2} + 13x + 30 = 0$
$\Rightarrow \ \ \ x = - 3,\  - 10$

Q. The coefficients of $x$ in the quadratic equation $x^{2} + bx + c = 0$ was taken as 17 in place of 13, its roots were found to be -2 and -15. The correct root of the original equation are

Explanation

Reviewed by Dr. Abubacker

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