Q. In which quadrant of the complex plane, the point $\frac{1 + 2i}{1 - i}$ lies?
A) Fourth
B) First
C) Second
D) Third
Explanation
(c)
Let $z = \frac{1 + 2i}{1 - i} = \frac{(1 + 2i)(1 + i)}{(1 - i)(1 + i)} = - \frac{1}{2} + \frac{3}{2}i$
Here, coefficient of $x$ is negative and $y$ is positive, therefore it lies in the second quadrant
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.