Q. If $\log{\left( x^{3} + y^{3} \right) - \log_{10}{(x^{2} + y^{2} - xy) \leq 2}}$, then the maximum value of $xy$, for all $x \geq 0,\ y \geq 0$ is

A) 2500
B) 3000
C) 1200
D) 3500
Explanation

(a)
Given, $\log_{10}{\left( x^{3} + y^{3} \right) - \log_{10}{\left( x^{2} + y^{2} - xy \right) \leq 2}}$
$\Rightarrow \ \log_{10}{\frac{(x^{3} + y^{3})}{x^{2} + y^{2} - xy} \leq 2}$
$\Rightarrow \ \log_{10}{(x + y) \leq 2 \Rightarrow x + y \leq 100}$
Using AM $\geq$ GM
$\therefore\ \ \frac{x + y}{2} \geq \sqrt{xy}$
$\Rightarrow \ \ \ \sqrt{xy} \leq \frac{x + y}{2} \leq \frac{100}{2}$
$\Rightarrow \ \ \ xy \leq 2500$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.