Q. The solution set of the inequation $\frac{x + 11}{x - 3} > 0$ is
A) $( - \infty,\ 11) \cup (3,\ \infty)$
B) $( - \infty,\ - 10) \cup (2,\ \infty)$
C) $( - 100,\ - 11) \cup (1,\ \infty)$
D) $( - 5,\ 0) \cup (3,\ 7)$
Explanation
(a)
$\frac{x + 11}{x - 3} > 0$
$\Rightarrow \ \ (x - 3)(x + 11) > 0$
$\Rightarrow \ \ \ x < - 11,\ x > 3$
$\Rightarrow \ \ x \in ( - \infty,\ - 1) \cup (3,\ \infty)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.