Q. $(x - 1)\left( x^{2} - 5x + 7 \right) < (x - 1),$then $x$ belongs to
A) $(1,2) \cup (3,\infty)$
B) (2, 3)
C) $( - \infty,1) \cup (2,3)$
D) None of these
Explanation
(c)
$(x - 1)\left( x^{2} - 5x + 7 \right) < (x - 1)$
$\Rightarrow (x - 1)\left( x^{2} - 5x + 6 \right) < 0$
$\Rightarrow (x - 1)(x - 2)(x - 3) < 0$
$\therefore x \in ( - \infty,1) \cup (2,\ 3)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.