Q. $(x - 1)\left( x^{2} - 5x + 7 \right) < (x - 1),$ then $x$ belongs to
A) $(1,\ 2) \cup (3,\ \infty)$
B) $( - \infty,\ 1) \cup (2,\ 3)$
C) 2, 3
D) None of these
Explanation
(b)
Given, $(x - 1)\left( x^{2} - 5x + 7 \right) < (x - 1)$
$\Rightarrow \ \ (x - 1)\left( x^{2} - 5x + 6 \right) < 0$
$\Rightarrow \ \ (x - 1)(x - 2)(x - 3) < 0$
$\Rightarrow \ \ x \in ( - \infty,\ 1) \cup (2,\ 3)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.