Q. The minimum value of $P = bcx + cay + ab\mathcal{z,\ }$when$\ xy\mathcal{z =}abc,\$is
A) $3abc$
B) $6abc$
C) $abc$
D) $4abc$
Explanation
(a)
Since, $AM \geq GM$
$\Rightarrow \frac{bcx + cay + ab\mathcal{z}}{3} \geq \left( a^{2}b^{2}c^{2} \bullet xy\mathcal{z} \right)^{1/3}$
$\Rightarrow bcx + cay + ab\mathcal{z} \geq 3\ abc\ \ \ \ (\because xy\mathcal{z =}abc)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.