(a) $\because\ \ \ \ \ \ \ \frac{n(n - 3)}{2} = 54$ $\Rightarrow \ \ \ \ \ \ n^{2} - 3n - 108 = 0$ $\Rightarrow \ \ \ \ \ \ \ \ \ (n - 12)(n + 9) = 0$ $\Rightarrow \ \ \ \ \ \ \ \ n = 12\ \ \ \ \ \ \ \ \ \ \lbrack\because n \neq - 9\rbrack$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.